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4k^2-56k+192=0
a = 4; b = -56; c = +192;
Δ = b2-4ac
Δ = -562-4·4·192
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-8}{2*4}=\frac{48}{8} =6 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+8}{2*4}=\frac{64}{8} =8 $
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